python3 http请求获取url内容 发布于:2019-03-23 Python 0条评论 3,674 views import urllib.request def get_page(url): res = urllib.request.urlopen(url) content = res.read().decode() return content str1 = get_page('https://www.bphc.com.cn/front/noroomstaff/checkHavePlanShow') print(str1) 上一篇 python 格式化日期 下一篇 从今天起,本号由于认证关系开始无限期停更,以后内容均会在个人微博@阿泽Anza 更新,欢迎大家关注,谢谢! r.text()).then(data => { count = data; liked = true; }); }" :class="liked ? 'bg-slate-100 dark:bg-slate-700 text-slate-400' : 'bg-orange-500 hover:bg-orange-600 text-white'" class="inline-flex items-center gap-2 px-6 py-3 rounded-xl font-medium transition-all duration-300 transform hover:scale-105" :disabled="liked"> 赞